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Is PyAny defined in PythonCall.jl? #19

@singularitti

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@singularitti

Hi, when I was reading your code, I found this line includes type PyAny, which seems to be defined only in PyCall, but not PythonCall:

(f::Figure)(args...; kws...) = pycall(Py(f), PyAny, args...; kws...)

Could it be a typo?

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